View Full Version : Battrick thread, Part III
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Bluto11
29 Sep 2005, 02:37 PM
Good day. Sold my guy for about 235k, and drew a bot in the cup. This means I can definitely GFI my league match, and the TIE the cup.
Awesome.
nice.
i'm playing GFI tomorrow and TIE in the cup against the bot as well. let's hope i start it out with a win!
I've also got 430,000 in the bank! I'm thinking of selling a few more players that I don't use. One guy is a competant batsmen, but with abysmal consitency, with an avg of 41.something. I listed him at 50,000 but am getting no takers. I'll keep trying.
Craig P
29 Sep 2005, 04:22 PM
I drew a newly-assigned squad, which should be winnable unless they got a ridiculous initial allocation of players.
What is the cup draw format, is it a random draw, HT-style, or some other variation?
kopiteinkc
29 Sep 2005, 04:44 PM
Player up for sale -- great all rounder:
Jonathan Thompson (51508)
RH Batsman, RH Spin Bowler, competent form, Healthy
An attacking player with woeful leadership skills and abysmal experience.
Plays For: KC Googlies
Nationality: England
Age: 22 Years Old
Battrick Rating: 9,442
Wages: £2,178 p/w
Stamina: mediocre Wicket Keeping: mediocre
Batting: strong Concentration: mediocre
Bowling: mediocre Consistency: feeble
Fielding: abysmal
Final amount = 620,000 -- hell yeah :D
Bluto11
29 Sep 2005, 05:04 PM
Final amount = 620,000 -- hell yeah :D
good lord. who has that amount of funds to splash around.
kopiteinkc
29 Sep 2005, 05:36 PM
good lord. who has that amount of funds to splash around.
I do now ;) :D
johno
29 Sep 2005, 08:34 PM
I've got 270K to mess around w/ now but I think I'll sit on it and maybe expand my stadium eventually.
kopiteinkc
29 Sep 2005, 09:58 PM
The stadium upgrade has started, I may have to name it Jonathan Thompson Stadium after my sale today :)
John_Harkes_6
29 Sep 2005, 10:42 PM
I just dropped 335 on a guy while Taking it Easy
Now to get 11 quick wickets
Bluto11
29 Sep 2005, 11:07 PM
I just dropped 335 on a guy while Taking it Easy
Now to get 11 quick wickets
nice, are you playing a bot?
you only need 10 wickets to end the match!
edit: i'm bored and found your match and it ain't no bot. nice job!
kopiteinkc
30 Sep 2005, 08:09 AM
Playing a tough opponent in the league today, I am 262-2 after 41 overs, should break 300. My bowlers should be able to keep him lower than that on my dusty pitch.
John_Harkes_6
30 Sep 2005, 08:30 AM
I drilled the guy - matchid - 135317
335 to 91 - I got back to back wickets 4 times :D
Top 2 bowlers:
Name O M R W nb wd
Emerton 10 1 40 2 1 0
Otsemobor 5 0 25 4 1 1
John_Harkes_6
30 Sep 2005, 08:37 AM
Someone help me out - how is Net RR calculated?
kopiteinkc
30 Sep 2005, 08:37 AM
Playing a tough opponent in the league today, I am 262-2 after 41 overs, should break 300. My bowlers should be able to keep him lower than that on my dusty pitch.
Finished at 331-3, very nice :D
Bluto11
30 Sep 2005, 09:46 AM
Someone help me out - how is Net RR calculated?
from the Battrick Rules page:
Appendix 1. Net Run Rate
As is now common in world one day cricket, Battrick uses some called Net Run Rate (NRR) to separate sides level on points in our OD league competition:
The following is how it is described within the rules of the actual game:
A team's net run rate is calculated by deducting from the average runs per over scored by that team, the average runs per over scored against that team.
In the event of a team being all out in less than its full quota of overs, the calculation of its net run rate shall be based on the full quota of overs to which it would have been entitled and not on the number of overs in which the team was dismissed.
Back with us? Good! Now let's try and explain that with a slightly more step by step approach.
A teams run rate is their total number of runs divided by overs faced. Now as an over is six balls if an over isn't completed then you need to do a little calculation to find what to divide by.
For example: 40.1 is actual 40 overs and one sixth of an over. Thus, for the purpose of the runrate calculation, the teams has faced 40 + 1/6 = 40.167 (3 d.p.) overs.
If another ball is bowled, they have now faced 40 + 2/6 = 40.333 (3 d.p.) overs. After the next ball (40.3 in normal terms) it's the more user friendly 40.5 as we're halfway through the over.
So if a team scores 250 runs off 50 overs then their runrate is 250/50 = 5. If they got that same score off 47.3 overs, there RR would be 250 / 47.5
Net Run Rate simply involves taking your opponents final runrate away from your own total runrate. The only slight exception is that now, if a team is bowled out, it is not the balls faced which their score is divided by; instead the full fifty over quota is used.
Here are a few scenarios: 1. Side that bats first wins
Team A bats first and sets a target of 287-6 off their full quota of fifty overs. Team B fails in their run chase, early losses causing them to struggle to 243-9
Team A's runrate is 287 / 50 = 5.74
Team B's runrate is 243 / 50 = 4.86
Team A's NRR for this game is 5.74 - 4.86 = 0.88 . If this was the first game of the season, their NRR for the league table would be +0.88
Team B's NRR for this game is 4.86 - 5.74 = -0.88 . If this was the first game of the season, their NRR for the league table would be -0.88
2. Side that bats second wins
Team A bats first and sets a target of 265-8 off their full quota of fifty overs. Team B successfully chases, getting their winning runs with a four with sixteen balls remaining, leaving them on 267-5
Team A's runrate is 265 / 50 = 5.12
Team B faced 47.2 overs and so their runrate is 267 / 47.333... = 5.64084... = 5.64 (2 d.p.)
Therefore Team A's net run rate for this game is 5.12 - 5.64084... = -0.52084... . If their net run rate for this season was previous +1.52 it is now +0.99916... = +1.00
Therefore Team B's net run rate for this game is 5.64084... - 5.12 = +0.52084... . If their net run rate for this season was coincidentally also previously +1.52 it is now = +2.04
3. Side that bats first is bowled out. Side batting second wins.
Team A bat first and are skittled out for 127 off 25.4 overs. Team B reaches the target for the loss of four wickets off 25.5 overs.
Despite Team A's runrate for the balls they faced being 127 / 24.667 = 5.19 (2dp) because they were bowled out their run rate is worked out over the 50 over quote; 127 / 50 = 2.54
Team B actually scored at a slower pace, however they managed to protect their wickets. Therefore they use their balls faced runrate; 128 / 25.833 = 4.95 (2 dp)
Team A's NRR for this match is 2.54 - 4.95 = -2.41 and would be added (adding a minus to a positive having the effect of subtracting) to their seasons NRR.
Team B's NRR for the match is 4.95 - 2.54 = +2.41 and would be added to their seasons NRR.
Side that bats second is bowled out. Side batting first wins.
Team A bat first and set a formidable 295-7 off their compliment of 50 overs. Team B never gets close, being bowled out for 184 off 35.4 overs.
Team A's runrate is 295 / 50 = 5.9
Team B's runrate is taken over 50 overs as they were bowled out; 184 / 50 = 3.68
Team A's NRR for this match is 5.9 - 3.68 = +2.22 and would be added to their seasons NRR.
Team B's NRR for the match is 3.68 - 5.9 = -2.22 and would be added to their seasons NRR.
5. Both sides are bowled out, the team batting first therefore taking the points.
Team A bat first manage 117 off 24 overs on a testing track. Team B fall agonizingly short, reaching 112 off 23.3 overs.
As they were bowled out Team A's runrate is 117 / 50 = 2.34 (2dp)
As Team B were also bowled out their run rate is 112 / 50 = 2.24 (2dp)
Team A's NRR for this match is 2.34 - 2.24 = +0.10 and would be added to their seasons NRR.
Team B's NRR for the match is 2.24 - 2.34 = -0.10 and would be added to their seasons NRR.
Obviously in a tied game the teams runrates are equally and so the teams NRR for that season would be unaffected.
Please Note: The Battrick engine stores run rate and net run rate figures to many more decimal places than used here in this examples
Andy P
30 Sep 2005, 10:06 AM
I think theres a problem with the NRR calculation at the moment, there was a team who won their match and got a -8 NRR.
I'm in good shape in my first match in II :) Got 321-6 and resticted them to 100-1 in their first 20 overs.
End of Over 20: 100-1, runrate=5.00, reqrunrate=7.40 (321-6)
John_Harkes_6
30 Sep 2005, 10:44 AM
Thank you both - the reason I asked and was confused is that I pummled the beejeezus out of the guy 335 (in 50 overs) to 91 (in 23.1 overs) so my net RR should have been 6.7-3.928 or 2.7719. However, it was showing me in 4th place in my division with a Net RR of -8.52 :eek:
Actually - since I bowled them out they should only have 1.82 so my Net RR should be 4.88
Bluto11
30 Sep 2005, 11:11 AM
no commentary for my match yet :(
however, my friend who is in Windies series IV has commentary.
kopiteinkc
30 Sep 2005, 11:53 AM
KC Googlies won by 19 runs.
KC Googlies 331-3
Dillbags CC 312-10
Phew, made it. Dillbags (he he) pushed me all the way. My spinner did the job on his tailenders and gave me the win :D
Bluto11
30 Sep 2005, 12:04 PM
well i've got commentary.
batting first i'm at 145-4 from 24 overs. not bad seeing as i lost 3 wickets within 6 balls.
johno
30 Sep 2005, 12:07 PM
I'm in OK shape... bowling first and have got his guys at
117-3 at exactly the halfway point w/ a runrate of 4.68... if I can keep them at that I should be able to win the game but unless they go very deep I expect to bowl them out rather than restrict their scoring over 50 overs.